Transcript. Ex 2.2, 4 Solve the following linear equations. (𝑥 − 5)/3=(𝑥 − 3)/5 (𝑥 − 5)/3=(𝑥 − 3)/5 5 (x − 5) = 3 (x − 3) 5x − 25 = 3 (x − 3) 5x − 25 = 3x − 9 5x − 3x − 25 = −9 2x − 25 = −9 2x = −9 + 25 2x = 16 x = 16/2 x = 8 Check:- ∴ LHS = RHS Hence Verified.
Transcript. Ex 5.1, 11 Solve the given inequality for real x: (3 (𝑥 −2))/5 ≤ (5 (2 −𝑥))/3 (3 (𝑥 −2))/5 ≤ (5 (2 −𝑥))/3 3 × 3 (x - 2) ≤ 5 × 5 (2 - x) 9 (x - 2) ≤ 25 (2 - x) 9x - 18 ≤ 50 - 25x 9x + 25x ≤ 50 + 18 34x ≤ 68 𝑥 ≤ 68/34 x ≤ 2 Hence, x is a real number which is less than or equal to
Simplify (2x-3)^3. (2x − 3)3 ( 2 x - 3) 3. Use the Binomial Theorem. (2x)3 + 3(2x)2 ⋅−3 +3(2x)(−3)2 +(−3)3 ( 2 x) 3 + 3 ( 2 x) 2 ⋅ - 3 + 3 ( 2 x) ( - 3) 2 + ( - 3) 3. Simplify each term. Tap for more steps 8x3 − 36x2 +54x− 27 8 x 3 - 36 x 2 + 54 x - 27. Free math problem solver answers your algebra, geometry, trigonometry
Precalculus. Solve for x 3^ (2x)-3^x-6=0. 32x − 3x − 6 = 0 3 2 x - 3 x - 6 = 0. Factor the left side of the equation. Tap for more steps (3x − 3)(3x +2) = 0 ( 3 x - 3) ( 3 x + 2) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. 3x − 3 = 0 3 x - 3 = 0.
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